Solved Numerical of 9th Class Chemistry Chapter 1

rizwan
By rizwan March 3, 2013 04:38

Solved Numerical of 9th Class Chemistry Chapter 1

Solved Numerical of 9th Class Chemistry Chapter 1 

Numerical 9th Class Solved Numerical of 9th Class Chemistry Chapter 1

Numerical 9th Class

Students are advised to note the numerical carefully. This is the Latest Numerical according to the new pattern of boards.

Question no: 1

Sulphuric acid is the king of chemicals if you need 5 moles of Sulphuric acid for a reaction. How many grams of it will you weigh?

Solution:

Molar mass of H2SO4 = 2 + 32 + 64

Moles of H2SO4= 5

Mass/Weight=?

Formula:

Unknown mass = moles * molar mass

= 5 * 98g

We will weigh 490g of sulphuric acid to get 5 moles  (Answer)

Question no: 2

Calcium Carbonate is insoluble in water. If you have 40g of it how many Ca+2 and Co3-2 ions are present in it?

Solution:

CaCo3      ———–>    Ca+2   +  Co3-2

1 Molecule of CaCo3 Gives 1 Ca+2 and 1 Co3-2 ions

Given Mass = 40g

Moles =?

Molar mass of CaCo3 = 100g

Formula

Moles = Given Mass/Molar Mass

Moles =  40/100 = 0.4

Number of Ca+2 ions = 1 (moles × NA)

= 1 (0.4 × 6.02 × 1023)

= 2.4 × 1023

Number of Co3-2 ions = 1 (moles × NA)

= 1 (0.4 × 6.02 × 1023)

= 204 × 1023

40g of calcium carbonate has 2.4 × 1023  Ca+2 ions and 2.4 × 1023 Co3-2 ions. (Answer)

Question no: 3

If you have 6.02 × 1023 ions of aluminum how many sulphate ions will be required to prepare Al2(SO4)3.

Solution:

  Al2(SO4) —————->  2Al+  + 3SO4-2

1 molecule of Al2(SO4)3 gives 2Al+3 ions and 3SO4-2 ions.

  • If we have 1 mole of Al2(SO4)3 then

Number of Al+3 Ions are = 2(6.02 × 1023)

Number of SO4-2 ions are = 3 (6.02 × 1023)

  • If we have ½ mole of Al2(SO4)3 then

Number of Al+3 ions are = 1/2 × 2 (6.02 × 1023)

= 6.02 × 1023

Number of SO4-3 ions are = 1/2 × 3 (6.02 × 1023)

= 9.03 × 1023

So if we have 6.02 × 1023 ions of aluminum then 9.03 × 1023 Sulphate ions will be required. (Answer)

Question no: 4

Calculate number of molecules in

A: 16g of H2CO3   

B: 20g of HNO

C: 30g of C6H12O6.

Solution:

A)     16g of H2CO3

Given mass = 16g

Molar mass = 2+12+48 = 62g

Moles of H2CO= ?

Formula:-

Moles = given mass/Molar mass

Putting the value of mass and molar mass in above formula you get

Moles: 16/62 = 0.26

Number of moles = ?

Formula:-

 Number of moles = Moles ×  NA

By putting the value

Number of moles = 0.26 ×  6.02 ×  1023

                                                   = 1.56 ×  1023

B)      20g of HNO3

Given mass = 20g

Molar mass = 1 + 14 + 48

= 63g

Moles = ?

Formula:-     Moles = given mass/ molar mass

By putting the value

Moles = 20/63 = 0.31

Number of moles = ?

Formula: – number of molecules = moles × NA

                                = 0.31 × 6.02 × 1023

                                                = 1.86 × 1023

C)      30g C2H12O6

Given mass = 30g

Molar mass = 72 + 12 + 96 = 180g

Moles = given mass/molar mass

= 30/180 = 0.76

Number of molecules = moles × NA

                                                                        = 0.76 × 6.02 × 1023

                                                                        = 4.57 × 1023 

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rizwan
By rizwan March 3, 2013 04:38
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59 Comments

  1. alisha September 9, 14:57

    where is numerrical no. 5 6 7 8 9 10??????????????????????????????????????????????????????????????????????????????????????????????????????????

    Reply to this comment
  2. hina May 6, 11:58

    I need complete solved exercises of Chemistry,physics,biology for both class 9 and 19 of recent year 2014 plz respond me I need your help

    regards
    Hina

    Reply to this comment
  3. xani April 22, 10:40

    where is 5,6,7,8,9 and10 numericals? any one know there is only 4 numericals but i need all..:( :) :P

    Reply to this comment
  4. usman fayyaz March 16, 13:27

    9 class ka chemistry ka numericals number 5678910 deyn plzplz plz

    Reply to this comment
  5. usman fayyaz March 16, 10:42

    5678910 kahaannn hain

    Reply to this comment
  6. alyan March 4, 13:59

    thanks but where are 56789 10….stupid

    Reply to this comment
  7. hafsa February 24, 18:43

    jis ne bhe upload kiya hain ap ko yeh nahi pta keh 5,6,7,8,9,aur 10 bhe hain?kam az kam woh tou solve kr keh upload kr dein plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz :'(

    Reply to this comment
  8. farhan ahmad January 28, 04:29

    very well

    Reply to this comment
  9. Zoya Ali Khan January 24, 18:08

    Where is 5,6,7,8,9,10 numericals????

    Reply to this comment
  10. Zoya Ali Khan January 24, 18:07

    Where is 5,6,7,8,9,10 numericals???????

    Reply to this comment
  11. M.Adnanramzan December 29, 10:30

    Sir G exam kub ho gay 9th kay
    reply wating, plz

    Reply to this comment
  12. ammadtariq December 20, 13:02

    ye bus 4 numerical ha baqi kider ha wo b solved kro

    Reply to this comment
  13. Ali Hassan December 18, 16:22

    I need 6th numerical of ch#6

    Reply to this comment
  14. hadia mughal December 10, 17:31

    fine numericalsss

    Reply to this comment
  15. Zainab November 19, 12:40

    thanxxxxxxxxxxxx

    Reply to this comment
  16. Zainab November 19, 12:39

    thanx but where is q no.5,6,7,8,9,10?

    Reply to this comment
  17. laraib November 19, 05:35

    plz upload the numericals of ch 5

    Reply to this comment
  18. laraib November 19, 05:31

    i need only chapter no.5 numericals.

    Reply to this comment
  19. Zoya October 30, 15:26

    Frands easy solution chemistry ka pilot le lo :D

    Reply to this comment
  20. Zoya October 30, 15:24

    Uff Allah baki k khaan hn?

    Reply to this comment
  21. Sadia October 20, 11:21

    plzzzzzzzzz upload 5 6 7 8 9 10 numericals of first chptr of chemistry urgently

    Reply to this comment
  22. tayyaba September 29, 14:59

    How many total atoms are required to prepare 60g of hno3?

    Reply to this comment
  23. muqddas September 8, 15:36

    thanks but 5678 kahan hainnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn i needdddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd give meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

    Reply to this comment
  24. ajmal September 1, 05:52

    q no 10 solve

    Reply to this comment
  25. SUMBUL ZEHRA August 18, 15:32

    WHERE IS 5,6,7,8,9,10

    Reply to this comment
  26. mannafarhsa August 13, 12:25

    I need 5,6,7,8,9,10 numericals of the 1st chapter and also provide me numerical solution of these chapters 5 and 6 …………………..plzzzzz snd me on this email address!!!!!!!!!!!!!!!!!!!!!!!!!!!!
    i’m vri thnx ful 2 u
    thnxs

    Reply to this comment
  27. kinza August 4, 06:34

    plz provied me the numerical of chemistry chapter no 5.

    Reply to this comment
  28. AZAN August 2, 01:26

    I need 5,6,7,8,9,10 numericals and notes of full book chemistry 9th class new edition

    Reply to this comment
  29. jannat princess July 22, 08:36

    plz answer the 5 6 7 8 9 10 numericals

    Reply to this comment
  30. zeeshan July 20, 13:31

    that’s are very tough notes i have notes of new chemistry that are very simple…..

    Reply to this comment
  31. pakiza butt July 16, 04:56

    thank you you’re a life saver

    Reply to this comment
  32. sana June 28, 06:55

    pls chp no.5 kay numericls bhej den

    Reply to this comment
  33. jannat June 18, 09:38

    where is 5 6 7 8 9 10 numericals

    Reply to this comment
  34. ishwa May 29, 10:28

    oh my GOD
    plzzzzzzzzzzzzzzzzz help me
    its tooo muucchhhh tough really

    Reply to this comment
  35. ishwa May 28, 10:26

    God bless u….
    to all my frndz………

    Reply to this comment
  36. hinagul May 28, 04:10

    kia
    likhoon

    Reply to this comment
  37. hinagul May 28, 04:08

    plz aap log hamain iss dafa ki chemistry ke notes de dain
    aur neumericals bhi send kar dain

    Reply to this comment
  38. adan May 16, 14:53

    bus 4 numerical q hain sir mjy to baqi ki b need hy :( :(:(
    ANYONE CAN HELP ME??????????????????????????
    I NEED UR HELP FRENDZ……………………………………..
    HELP ME HELP……………………………..
    HELP…………………………..
    m waiting for help aboutt numerical :( ^_^ :(

    Reply to this comment
  39. Muhammad Rahim May 12, 07:45

    Thanks u very much.God bless u.

    Reply to this comment
  40. malauka khan May 7, 03:32

    i want 5 6 7 8 9 10 also plz help me
    and thanx for this

    Reply to this comment
  41. rana abdul April 5, 13:39

    thnkuuu

    Reply to this comment
  42. sharjeelhaider March 26, 05:21

    more notes

    Reply to this comment
  43. abdulbasit March 20, 09:36

    thnkx

    Reply to this comment
  44. Malik Adeel March 14, 17:42

    Do u have solved only 3 numericals?

    Reply to this comment
  45. usman akram March 5, 15:32

    english 9th class urdu mediam

    Reply to this comment
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